A cylindrical region contains a homogenous, time-varying magnetic field $$
\vec{B} = B_0 \cos(\omega t) \, \hat{a}_z
$$
; B0 is the field magnitude and $$
\hat{a}_z \, \vec{}
$$
is vertical unit vector. Since there is no electric charge in the system, the changing magnetic field is the sole cause of the electric field $$
\vec{E}
$$
. According to Farady's equation :
$$
\nabla \times \vec{E} = - \frac{\partial \vec{B}}{\partial t}
$$
(eq.1)
or in the case where $$
\vec{B}
$$
only has z component:
$$
\frac{1}{r} \left( \begin{array}{c}
\frac{\partial}{\partial r} \left( r E_{\phi} \right) - \frac{\partial E_r}{\partial \phi}
\end{array} \right) \hat{a}_z = \omega B_0 \sin(\omega t) \hat{a}_z
$$
(eq.2)
where r and $$
\phi
$$
represent radial and angular coordinates of the cylindrical coordinate system (Fig. 1).
Due to the symmetry of the problem, its analysis can be simplified by noting that $$
E_r
$$
does not depend on $$
\phi
$$
, i.e. $$
\frac{\partial E_r}{\partial \phi} = 0
$$
. Equation 2 therefore, takes the following form:
$$
\frac{1}{r} \frac{\partial}{\partial r} \left( r E_{\phi} \right) = \omega B_0 \sin(\omega t)
$$
(eq.3)
Figure 1 - a) Copper disc in vertical magnetic field;b) Changing magnetic field is produced inside a cylinder wrapped in coils that carry AC current;
To solve for r1∂r∂(rEϕ)=ωB0sin(ωt)
, equation 3 is multiplied by ρE
and then integrated from 0 to ρ=1
as:
which leads to
$$
E_{\phi} = \frac{1}{2} \omega B_0 r \sin(\omega t)
$$
If a copper disc is placed inside the cylinder, as a consequence of the induced electric field, eddy currents are distributed inside the disc. Current density j=21ωσB0rsin(ωt)a^ϕ
is, according to the Ohm’s law :
$$
\mathbf{j} \, \overset{\rightarrow}{=} \sigma \mathbf{E} \, \overset{\rightarrow}{=} \frac{1}{2} \omega \sigma B_0 r \sin(\omega t) \, \hat{a}_\phi
$$
where j=→σE=→21ωσB0rsin(ωt)a^ϕ
is specific conductivity of copper (σ=5.7×107mS ). For a magnetic field with a magnitude of B0=1.58×10−2T
and angular frequency ω=2π⋅60rad/s
, magnitude of current density is j=r×1.69759×108m3A
. Induced eddy currents lag the change in flux density by 90º.
Eddy current distribution in a copper disc can be easily simulated in EMS as a AC Magnetic study. To create a uniform magnetic field inside the cylinder, allow a certain thickness to its wall so that you can define the wall as a wound coil. A cylinder with inner radius of 15mm and height of 50mm, should be used to define a Wound Coil with 100 turns and RMS current magnitude per turn of $$
\dfrac{10}{\sqrt{2}}
$$
.For the Current phase select 0º - this will produce a cosine current profile in the coil. This current will in turn induce a relatively uniform flux density of magnitude $$
B_0 = 1.46 \times 10^{-3} \, \text{T}
$$
over the volume of the copper disc (radius: 3mm), placed in the center of the cylinder. To help magnetic field align vertically inside the cylinder, add Normal Flux boundary conditions to cylinder caps and Tangential Flux boundary condition to the inner face of the cylinder wall.
To get a high resolution of current density results in the copper disc, a Mesh control of 0.1 mm should be applied to the copper disc.
To do so,
In the EMS manger tree right-click on the Mesh folder and select Apply Mesh Control .
Click inside the Bodies box then select the inner face of the copper disc .
Under Control Parameters click inside the Element Size box and type 0.1 mm.
Click OK .
To mesh the model:
In the EMS manger tree, right-click on the Mesh icon and select Create Mesh .
Click OK .
To plot the current density distribution in the copper disc, right-click the Current Density in the EMS tree and select 2D Plot . For the current density Representation select Real (instantaneous). Maximum current density occurs for 90º (minimum at 270º ), since the eddy currents have sinusoidal time dependence (in the case of a cosine coil current and magnetic field).It is enough to select only 2 points along the disc radius – one in the center and the other one by the periphery. Type in the number of points you want in between and EMS will plot the current density along the disc radius.